4x^2=32x^2-36x

Solution for 4x^2=32x^2-36x equation:

4x^2=32x^2-36x

We move all terms to the left:

4x^2-(32x^2-36x)=0

We get rid of parentheses

4x^2-32x^2+36x=0

We add all the numbers together, and all the variables

-28x^2+36x=0

a = -28; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-28)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-28}=\frac{-72}{-56}
=1+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-28}=\frac{0}{-56}
=0
$